$3a^2-3$
$\frac{3x^3-4x^2+5x^1+6}{3x+2}$
$\left(4x+6\right)^{\cos\left(x\right)}$
$7x-4=5x+6$
$\lim_{x\to0}\left(\frac{1-e^{\left(3\left(x^2-1\right)\right)}}{4x}\right)$
$\left(-2x+b-6c\right)-\left(-4x-3b-2c\right)$
$\frac{9-x^2}{x+2}$
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