$\frac{3-x^2}{x^2-5}$
$\frac{x^5-x^4+x^2-3}{x^2+1}$
$x^2+y^2-1+1$
$\left(\frac{\left(1-i\right)}{k+4-3i}-\frac{\left(1-i\right)}{k+5-3i}\right)$
$6a\:\left(4a\right)$
$\lim_{x\to\infty}\frac{x-6}{x^2+4x+7}$
$x^2+x+3+x^2-3x$
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