$\sqrt{125x^5}$
$\left(5x^2\right)^2$
$\left|3\right|\left|4\right|\cdot\left|5\right|\left|6\right|^3$
$y'+4y=e^x$
$\left(2+\sqrt{3}\right)+\left(2-\sqrt{3}\right)+1$
$x\cdot\frac{dy}{dx}=x^2\cdot y^2$
$753+27+395$
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