$-6x^2+3x+18$
$\sqrt[12]{27x^3}$
$\sqrt[5]{x^2}-\frac{17}{\sqrt[5]{x^3}}+\frac{1}{64\sqrt[5]{x^3}}$
$3^3+-6^4-2$
$3\cdot\left(4+6\right)$
$x+4=y^2$
$9m^8+27m^4-36$
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