$\left(2xy^2+4m\right)^3$
$\lim_{t\to7}\left(\frac{t\left(7-t\right)^2}{49-14t+t^2}\right)$
$log3\left(2x+1\right)+7=9$
$\left(6+8\right).2+18\cdot\left(5+4\right)$
$8x^3+4x^2-2x+6$
$x^2+5x-14=0$
$\left[9-\left(+8\right):\left(-4\right)\right]:\left(+11\right)-\left(+6\right):\left(-3\right)$
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