$-8\left(-2\right)+3\left(7\right)-5$
$2x\:y\:y'0$
$\pi\cdot2.1^2+4.6$
$\int\frac{x-4}{\sqrt{3x^2-6x-12}}dx$
$\sqrt[3]{\sqrt{x^2}}$
$\left(-1-\left[-19\right]\right)$
$-6-8-\left(-6\right)$
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