$3a+5b\left(2\right)$
$3w^2-5w+3=5$
$-3+\left(2\right)\cdot\left(-3\right)$
$-2x+9>6$
$\left(-6x^{3}y^{4}\right)^{2}$
$\left(2x-3\right)^2=\left(x+3\right)^2$
$\int\frac{\left(x^2+x+3\right)}{x^4+6x^2+9}dx$
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