$\left[46\:-\:13\right]\:-\:\left[24\:-\left(-32\right)\right]\:$

$x-5>0$

$\frac{dy}{dx}-2y=x^2+5$

$\left(x-6\right)dx=\left(y+3\right)dy$

$\frac{dx}{du}=\sin\left(3u\right)\cos\left(3u\right)$

$\log\left(\left(2x+5\right)^{2}\right)=4$

$\int\frac{secx}{secx+tanx}dx$