$3x+9=15$
$\frac{x^5+2x^3-3}{x-1}$
$\frac{8+2i}{6-4i}$
$ax+3ax+8ax$
$\frac{5x-4}{x^2-1}-\frac{4x-3}{x^2-1}$
$\left(2cos\left(x\right)-1\right)\left(2cos\left(x\right)-3\right)=0$
$\left|\left(-6+5\right)\right|+2$
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