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Exercise

$\frac{3x+3y}{20xy}+\frac{3x-3y}{20xy}$

Final answer to the exercise

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Other solved exercises

$z^2-13z+40$

$2\left(3\right)-\left(-2\right)$

$4x^2+20x+24$

$4\cdot0^2$

$4x^3+1+2$

$2a^{-1}\cdot3a^2$

$809.787375+1.357123375$
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