$1\left(-2\right)^2-3\left(-2\right)+1$
$\left(-4\right)\left(-2\right)\left(+8\right)\left(+25\right)\left(-5\right)$
$\frac{3}{x+2}\leq4$
$0.10x=\:327\:-\:0.115y\:$
$65+6-\left(-1\right)+5$
$3x^2-8x$
$\lim_{x\to2}\left(\frac{x^2+3x+2}{x^2-x-6}\right)$
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