$\frac{3}{4}\sin\:\left(x\right)-\sin\:^3\left(x\right)=\frac{1}{4}\sin\left(3x\right)$

$\left(2x\:-\:12\right)^3$

$\int re^{\frac{1}{2}}dr$

$6\left(3x+3y\right)$

$\left(\csc\left(x\right)+\cot\left(x\right)\right)=\frac{1+\cos\left(x\right)}{1-\cos\left(x\right)}$

$\frac{16}{11}\cdot1.4$

$\left(3p+2q^2\right)^3$