$\int\left(\frac{3}{4x+1}\right)dx$

$\frac{y'}{y\left(x+1\right)}=1$

$\left(y^3-x\right)\left(y^6+xy^3+x^2\right)$

$\lim\:_{x\to\:\infty\:}\left(\frac{3x+4}{3x-2}\right)^{2x+1}$

$2x\left(n-2\right)\:-\:3y\left(n-2\right)$

$\lim_{x\to0}\frac{5x^3}{x^2-3x+2}$

$\int\left(\frac{x^3+2x^2-4}{x^2}\right)dx$