$5x+1>5$
$f'\left(x\right)=\left(1+3x\right)^2$
$15x^{3}y^{5}-20+5y^{2}z$
$4x^2-35x+44$
$-46.\:-46.\:-46$
$\int t^2e^{-.05t}dt$
$\frac{\tan\:\left(2x\right)}{2\sin\left(x\right)\cos\left(x\right)}=\frac{1}{\cos\left(2x\right)}$
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