$\frac{dx}{dy}=y\left(x+1\right)^2$
$20y^3-80y^2-100y=0$
$2xz+z^2$
$\int\:in\:x^2\:dx$
$\left(\frac{1}{2}y\right)^2$
$\int\frac{1}{\sqrt{196-x^2}}dx$
$\left(sinx\right)\left(3cosx-1\right)=0$
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