$9x+8=7x+6$
$7\:-\:5c^2d^{3\:}-\:cd^4\:+\:3d^3c^2\:-\:d^4c\:-\:1$
$\int\left(9\left(3x-4\right)^{-3}\right)dx$
$\left(1+\frac{2}{x}\right)^{-0.5}$
$\left|14\right|$
$f\left(x\right)=4x^5-5x^4$
$10x^3y-y^2-2x^3y^2$
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