$n+12\le3$
$\left(x^2-5x-24\right)\left(x+3\right)$
$2^6-\left(5^3-\:4^3\right)$
$\frac{x^2+3x-2}{x+3}$
$-\left(3a^m-8\right)\left(3a^m+8\right)$
$y=\left(2x-4\right)^5\left(6x^2-3\right)^2$
$a^2\cdot5a\left(m-1\right)b^x$
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