$\int\frac{5}{\left(4-2x\right)^2}dx$
$2+4x+4$
$72\:x\:+28$
$\int\left(\frac{9x-16}{3x^2-14x+8}\right)dx$
$2tan\left(\frac{x}{2}\right)+3^{0.5}=0$
$14,494+\left(-282\right)$
$10x^2\:-\:9x\:+\:6$
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