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Rationalize the denominator $\frac{3}{\frac{\sqrt{2\cdot 7+3}-7}{7-3}}$

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Algebra 1 - Solve an equation with a rational term 1/x= 3+ 7/x^2+7x ex 2

https://www.youtube.com/watch?v=OjNDpBeMpxI

Algebra 2 - Learn to solve a rational equation by multiplying by the LCD (15/x)+((9x-7)/(x+2))=9

https://www.youtube.com/watch?v=BMSmvkWcVTU

Algebra 2 - Why and how to we apply synthentic division (2x^3 - 3x^2 - 10x + 7) / (x-3)

https://www.youtube.com/watch?v=uHKLxnsw1Yo

Pre-Calculus - Mulitplying by the LCM to simplify a complex fraction, (1/4 + 2/3)/(5/6 - 1/12)

https://www.youtube.com/watch?v=Cz-Gq4tqQ6c

Tutorial - Dividing complex numbers ex 20, (7 + 4i)/(2 - 3i)

https://www.youtube.com/watch?v=Vkw5VpMG9TI

Tutorial - Misconception multiplying by the same number to both fractions, 3/8 + 2/5

https://www.youtube.com/watch?v=evBElviu0MY

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Rationalisation

In elementary algebra, root rationalisation is a process by which radicals in the denominator of an algebraic fraction are eliminated.

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