$\left(2x^3-\frac{2}{5x^2}\right)^2$
$\left(-4\right)\left(-3\right)\left(1\right)\left(-2\right)$
$5\left(s+1\right)$
$\tan^22x-3=0$
$7.16-10009$
$6mn^2-3m^2$
$\lim_{x\to4}\left(\frac{\sqrt{x-3}-1}{x^2-1}\right)$
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