$y^2+\left(\frac{5y}{25}\right)+10$
$10\left(7r-7\right)$
$cos\:x=\frac{1}{\sqrt{2}}$
$4x-8<x-2$
$-2x+9>6$
$\int\frac{6x^2-10}{x^3-5x}dx$
$9-4-\left(2-5+2\right)-7+3-9$
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