$\left(7\right)\cdot\left(6\right)\cdot\left(-2\right)$
$3\left(2x-5\right)^2$
$41.19-4.10$
$\log\:_{10}\left(6x-1\right)-\log\:_{10}\left(x+4\right)=0$
$36x^2-x^2-2x-1$
$\frac{v-4}{2v+4}$
$\frac{-3x^2-x+2}{3x-1}$
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