$\int\left(6x^2\cdot e^3\right)dx$
$0t-9t+6u+4u^5$
$5^{9-\left(-3\right)^2}$
$\left(1+x^2\right)\frac{dy}{dx}=x\:tany\:$
$\frac{9u^5}{3u^6}$
$\int\frac{1}{\sqrt{49+9x^2}}dx$
$\int\frac{x^2-x+14}{\left(x-4\right)^3\left(x-2\right)}dx$
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