$\frac{\cot\left(x\right)+1}{\cot\left(x\right)}=1+\tan\left(x\right)$

$\int\frac{\left(7x+3\right)}{\left(x+1\right)^2}dx$

$\frac{\left(\frac{\sin\left(x\right)}{\cos\left(x\right)}\right)}{\sin^2\left(x\right)}.\frac{1}{\sec^2\left(x\right)}=1$

$48x^4y-96x^2y^3$

$\lim_{x\to-4}\left(3\right)$

$12x-9$

$-4\:.\:-16$