$\left(-15-8\right)+\left|-\left(12+0-3\right)\right|$
$\frac{x^4+3x^2+x+8}{x^3+4x}$
$3\cdot0+9\le-7$
$\left(\frac{3x}{3x-2}\right)+\frac{\left(3x-2\right)}{2x+3}$
$8+9x\le7$
$x^2+1=3x^2$
$4096\cdot256\cdot4$
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