$\left(4x^7-x^5-\frac{4}{7x^4}-8\right)$
$\left(a+\frac{1}{a}\right)^2=3$
$\left(a+b=5\right)\left(a.b=7\right)$
$2x^2+6x+8x^3-12x^4$
$\left(7-\left(-6\right)\right)\cdot\left(-12\right)$
$2x^2-14x-3x$
$\frac{dy}{1-4y}=xdx$
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