$16x^2+24x+9=0$
$\left(4a^2b\right)\left(\frac{-9^3}{2b}\right)$
$\frac{dx}{dv}=\frac{x\ln\left(x\right)}{v}$
$\frac{1}{2}w-\frac{3}{5}w$
$\int8xe^5dx$
$\sqrt{\ln\left(e^5\right)}$
$y'+25y=0$
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