$\frac{x^3}{x^2-x}$
$\frac{3}{4z+2}=\frac{1}{z+2}$
$x^3-3x^2-18x+40$
$\frac{dy}{dx}=-e^xy^2$
$\frac{d}{dx}\left(4x^3-\:7xy^2=\:2y^3\right)$
$2x+1\:+\:2x-1\:area$
$\frac{d}{dx}x^2+y^2=r^2$
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