$x^2-20x=5$
$\frac{4}{3}\cdot60$
$14+370+212$
$-5>\frac{f-87}{2}$
$3\left(a^2\right)^2-\left(6b^2\right)^2$
$3x+1>x-15$
$\frac{2x^3-3x+2}{x+3}$
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