$3\frac{dy}{dx}=\frac{6y+5x}{2x}$
$\left(40\right)\cdot\left(-4\right)$
$\frac{6x-3}{x+2}\le5$
$8x^2-5x\:=\:0$
$54.784-34.001$
$x+y+z=11\:$
$36x^4-16y^8$
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