$-4-4\cdot8$
$\int\frac{sec^2\left(3\sqrt{x}\right)}{\sqrt{x}}dx$
$4\sin^2\left(x\right)=1-cos^2\left(4x\right)$
$ln\left(9x+36\right)=ln\left(7x+22\right)$
$\frac{a^{-8}}{a^3}$
$\frac{\left(x^3-4\right)\left(6x+2\right)^4}{sqrt\left(2x^5+1\right)}$
$\int-x^2\:dx$
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