$x4y-2xy+3xy$
$x\cdot y'+3y=\frac{1}{x}$
$\frac{dy}{dx}=\frac{1}{3\sec\left(2x\right)}$
$\int secx^2tanx^2x\:dx$
$y=\sqrt[7]{x\left(3x^2-3x+4\right)}$
$-6x^5y^5\left(11x^5\right)$
$\left(2x-y\right)\left(3x-y\right)$
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