$\int10x\cdot sec^2\left(x\right)dx$
$\int\frac{\left(x+4\right)^2}{x^4}dx$
$\frac{dy}{dx}=x+x^2$
$a^3x^3+2a^3x^2y-4a^3xy^2-8a^3y^3\:$
$24x^3-28x^2+8x$
$2x^2+3x+2>-10$
$x^2-60x+576$
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