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$\frac{2x\sec^2x^2}{\sqrt[3]{9\tan^2x^2}}$

Final answer to the exercise

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Other solved exercises

$\frac{\left(x^3+2x\right)^4}{sin\left(x\right)\sqrt[5]{7x+5}}$

$8.93+0.16$

$13b-18c+15b+17c-17c-13a+8b-9a$

$\csc=\frac{3}{4}$

$3x^2+14x+8$

$\left(3x\:-\:4y\right)\:\left(3x\:+\:10y\right)\:$

$4^2+3x+-11$
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