$\int\frac{1}{x\left(x^2+x+1\right)}dx$
$3-\left(4-7-2\right)+\left(-5+8-1\right)$
$3\left(x-4\right)=2\left(-2x+1\right)$
$\left(4x^3y^3\:+\frac{1}{x}\right)\:dx\:+\:\left(3x^4y^2\:-\frac{1}{y}\right)\:dy\:=\:0$
$\left(50-120\right)-\left(-40+120\right)$
$=\cos^2x+3\cos x-4$
$35y-14y^2+21y^3$
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