$\int\frac{1}{\left(x-1\right)\left(x+3\right)^2}dx$
$\left(2x-5y+3z\right)\left(x^2-y\right)$
$-3x-5=10$
$100a^{10}-60a^5^b^4-9b^8$
$xy\:=\:1\:+\:x^2$
$\:\:\frac{x-9}{2\:\sqrt[2]{x}-6\:}\:\:\:$
$6\cos\:^{\left(2\right)}x+cosx-2=0$
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