$\sqrt[4]{x^{10}y^8}$
$\frac{\left(x-2\right)\left(x-3\right)}{x-1}$
$-6x^3\cdot x\cdot y^2\cdot y^6$
$\sqrt[3]{3^6.2^3}$
$9x^2+24x-48$
$2,63x\:1,78x\:0,597$
$\left(x+\frac{2}{3}\right)^2\left(x+\frac{2}{3}\right)^2$
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