$\left(x^3\right)^3+3\cdot\left(x^3\right)^2\cdot2y+3\cdot x^3\cdot2y^2+2y^3$
$7\cdot8\cdot6-15$
$\int6t^3dt$
$\left(4p^2q^3+3r^5\right)\left(4p^2q^3+3r^5\right)$
$\left(5x^3-2y^4\right)^2$
$\frac{2x^5-14x^3+x^2+28x-15}{x^2-5}$
$y-2xy=1$
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