$\frac{1+\cos\left(x\right)}{1-\sin\left(x\right)}=\left(\tan\left(x\right)\right)^2\left(\frac{1+\sin\left(x\right)}{1-\cos\left(x\right)}\right)$
$x=4^y$
$19-\left(1-4x\right)-9x+30$
$\frac{-48}{-3}$
$x^2-6x+5x-30+x^2+x-2$
$\int x\left(3-e^x\right)dx$
$\frac{dy}{dx}=-3x^2y=e^{x^3}$
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