$cos\left(x\right)-\frac{\cos\left(x\right)}{1+\sin\left(x\right)}=\tan\left(x\right)$
$3p^3q\:-7pq^2+8pq$
$\frac{d}{dx}12x^2-8x-4x^{-2}$
$3xy\:-\:8xy\:+\:6xy\:-7xy$
$\lim_{x\to0}\left(3^x-e^x\right)^x$
$x^3-13x+12$
$\:\cos\:^2\left(2x\right)-\sin\:^2\left(2x\right)=cos\:4\:x$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!