$\frac{\tan^2\left(x\right)}{\sec\left(x\right)-1}$
$x^2+2x-35<0$
$x\frac{dy}{dx}+2y=\frac{sin\left(x\right)}{x}$
$\int\frac{t^5}{\sqrt{t^2+1}}du$
$\int_3^6\frac{ln^2x}{x}dx$
$-5-7-9+1+3+5-10+12-8$
$\frac{dy}{dx}+10y-100=0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!