$y=\ln\sqrt{4-x^2}$
$4-2m+4m+1$
$\lim_{x\to0}\left(\frac{x\cdot\cos\left(x\right)}{\left(x+1\right)\sin\left(x\right)}\right)$
$\int\left(x^2-2\right)sin\left(2x\right)dx$
$\frac{dy}{dx}-2\sqrt{x}=5y\sqrt{x}$
$t^2+14t=-39$
$\int\left(\frac{9x-16}{3x^2-14x+8}\right)dx$
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