$x^5-3x^{3\:}$
$v\cdot\frac{dv}{dx}=v^2$
$2x-4\le0$
$4\cos\left(x\right)\sin\left(x\right)+2\sin\left(x\right)-2\cos\left(x\right)=1$
$-\left(-1-2x\right)^3$
$\frac{5g^{-5}}{3g^{-3}}$
$x^2-\frac{2}{5}x=-1$
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