Final Answer
$\frac{\frac{4}{5}\left(x+y\right)}{x-y}$
Step-by-step Solution
Problem to solve:
$\frac{24\left(x+y\right)^3\left(x-y\right)^2}{30\left(x+y\right)^2\left(x-y\right)^3}$
Solving method
1
Simplify the fraction $\frac{24\left(x+y\right)^3\left(x-y\right)^2}{30\left(x+y\right)^2\left(x-y\right)^3}$ by $x+y$
$\frac{\frac{4}{5}\left(x+y\right)\left(x-y\right)^2}{\left(x-y\right)^3}$
2
Simplify the fraction by $x-y$
$\frac{\frac{4}{5}\left(x+y\right)}{x-y}$
Final Answer
$\frac{\frac{4}{5}\left(x+y\right)}{x-y}$