$a^3+\frac{1}{a^3}$
$\sqrt{4\cdot36}$
$\frac{x^3-6x^2-7x+60}{x-4}$
$\left(7a-2\right)^2$
$\lim_{x\to\infty}\left(\frac{2}{3}\right)^x$
$-a^2+3a+28$
$\frac{k}{k+1}+\frac{1}{\left(k+1\right)\left(k+2\right)}=\frac{k+1}{k+2}$
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