$4\left(3+2\right)-4\left(4-10\right)$
$a^6-b^2\:x^8$
$2x^2=x$
$\int\frac{3x^2+10x+24}{x+1\left(x^2+16\right)}dx$
$p\left(-4\right)\:=\:_{\left(-4\right)}^3+\:7\left(-4\right)^2+\:5\left(-4\right)\:-28$
$11\sec\left(x\right)+4=19$
$x^4+2x^3+x^2$
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