$1x^3+4x^2+1x^1-6x^0$
$3x^2-4x+4\:=2$
$\left(3y+2\right)^5=\:4x^3-2x$
$\left(x^2+2x+5\right)=0$
$\frac{8x^2+6x^3-23x^2+mx-n}{4x^2-3x+1}$
$\int\frac{\left(u^2+1\right)}{u^4+1}du$
$5\:x\:=\:20$
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