$\frac{1}{1+\tan\left(x\right)}=1$
$\frac{4x+-3}{3}=-1$
$\frac{6o}{24}$
$\int\frac{\ln\left(x\right)}{-3x^2}dx$
$\left(5xz+3\right)^3$
$x\left(m+n\right)-x^2-xy+y\left(m+n\right)$
$\frac{1}{3}n-\frac{5}{3}n$
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