$\int\frac{1}{x^2\left(x+4x+9\right)}dx$

$\left(m-2b\right)\left(m+2b\right)$

$\left(\left(-4^0\right)\right)^5$

$\frac{2+tan^2\left(x\right)}{sec\left(x\right)}-1$

$-sen^2\:x\:+\:\left(cos^2\:x\:sen\:x\right)$

$1+cot^2=-\frac{9}{4}$

$\int_{-\pi2}^{\pi2}\cos\left(x\right)x^2dx$