$\left(3y\:5\:\right)\left(5y\:4\:\right)$
$\frac{x^6-64}{x^3-8}$
$\frac{dx}{dy}=\frac{1}{x+y+1}$
$2,5\:.\:4$
$-4-\left|-4\right|$
$1+\frac{1}{\sin^2\left(x\right)}=\frac{3}{\tan\left(x\right)}$
$\left(4x^3-5y^4\right)^2$
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