$\left(3b^2+2x\right)\left(3b^2+4x\right)$
$\left(-2\right).\left(-2\right).\left(-2\right).\left(-2\right).\left(-2\right).\left(-2\right)$
$\int\frac{7}{5}\csc xdx$
$27x^3+216$
$x-16^2$
$\frac{p^5-p^5}{p+p}$
$4x^2-18x+13$
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